standard form of a point that goes through-2,4 and the slope is -1/7

Answer:Standard form of a line passing through (-2, 4) and having slope of  -1/7 is x + 7y = 26 Solution:Given that we need to determine standard form of a line that goes through (-2 , 4) and slope of the line is -1/7Standard form of line passing through point ( a , b ) and having slope m is given by(y – b) = m ( x – a)   --------(1)In our case given point is ( -2 , 4 ) and slope is -1/7 that meansa = -2 , b = 4 , m = -(1/7)On substituting given value of a , b and m is equation (1) we get[tex](y-4)=\left(-\frac{1}{7}\right)(x-(-2))[/tex][tex]=>(y-4)=\left(-\frac{1}{7}\right)(x+2)[/tex]=> 7( y - 4 ) = -x – 2=> 7y + x = -2 + 28=> x + 7y = 26  Hence standard form of a line passing through (-2,4) and having slope of –(1/7) is x + 7y = 26